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Popular >

3y+x^4y^'=2xy

Solution

3 y + x^{4} y^{^{'}} = 2 x y

Solution

y = e^{- \frac{1}{x ^{2}} + \frac{1}{x ^{3}} + c_{1}}

Solution steps

3 y + x^{4} y^{'} (x) = 2 x y

Solve separable ODE:

y = e^{- \frac{1}{x ^{2}} + \frac{1}{x ^{3}} + c_{1}}

y = e^{- \frac{1}{x ^{2}} + \frac{1}{x ^{3}} + c_{1}}

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Frequently Asked Questions (FAQ)

What is the solution for 3y+x^4y^'=2xy ?
The solution for 3y+x^4y^'=2xy is y=e^{-1/(x^2)+1/(x^3)+c_{1}}