What is the derivative of h(θ)=θcos(θ) ?

The derivative of h(θ)=θcos(θ) is cos(θ)-θsin(θ)

What is the first derivative of h(θ)=θcos(θ) ?

The first derivative of h(θ)=θcos(θ) is cos(θ)-θsin(θ)

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derivative of

h (θ) = θ cos (θ)

cos (θ) - θ sin (θ)

Solution steps

\frac{d}{d θ} (θ cos (θ))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = θ, g = cos (θ)

= \frac{d}{d θ} (θ) cos (θ) + \frac{d}{d θ} (cos (θ)) θ

\frac{d}{d θ} (θ) = 1

\frac{d}{d θ} (cos (θ)) = - sin (θ)

= 1 \cdot cos (θ) + (- sin (θ)) θ

Simplify

= cos (θ) - θ sin (θ)

\int \frac{x y ^{2}}{x ^{2} + 1} d y

x \to - \infty lim (tanh (x))

\int sec (t) tan (t) d t

g (x) = x^{2} (1 - 4 x)

\frac{d}{d x} (e^{x} (1 - x^{2}))

What is the derivative of h(θ)=θcos(θ) ?
The derivative of h(θ)=θcos(θ) is cos(θ)-θsin(θ)
What is the first derivative of h(θ)=θcos(θ) ?
The first derivative of h(θ)=θcos(θ) is cos(θ)-θsin(θ)