What is the derivative of f(x)= 8/(sqrt(x)) ?

The derivative of f(x)= 8/(sqrt(x)) is -4/(x^{3/2)}

What is the first derivative of f(x)= 8/(sqrt(x)) ?

The first derivative of f(x)= 8/(sqrt(x)) is -4/(x^{3/2)}

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derivative of

f (x) = \frac{8}{x}

- \frac{4}{x ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{8}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 8 \frac{d}{d x} (x^{- \frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 8 (- \frac{1}{2} x^{- \frac{1}{2} - 1})

Simplify

8 (- \frac{1}{2} x^{- \frac{1}{2} - 1}) : - \frac{4}{x ^{\frac{3}{2}}}

= - \frac{4}{x ^{\frac{3}{2}}}

x y^{^{'}} = 3 x^{3} y^{\frac{1}{2}} - 2 y

\frac{s}{( s + 1 ) ^{2} + 1}

\frac{d}{d x} ((x - x + 6 x^{4})^{3})

\int (x^{3} (1 + x^{2}))^{- 1} d x

(t + 6)^{3}

What is the derivative of f(x)= 8/(sqrt(x)) ?
The derivative of f(x)= 8/(sqrt(x)) is -4/(x^{3/2)}
What is the first derivative of f(x)= 8/(sqrt(x)) ?
The first derivative of f(x)= 8/(sqrt(x)) is -4/(x^{3/2)}