What is the derivative of (8+7x^4) ?

The derivative of (8+7x^4) is 28(8+7x)^3

What is the first derivative of (8+7x^4) ?

The first derivative of (8+7x^4) is 28(8+7x)^3

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\frac{d}{d x} ((8 + 7 x)^{4})

28 (8 + 7 x)^{3}

Solution steps

\frac{d}{d x} ((8 + 7 x)^{4})

Apply the chain rule:

4 (8 + 7 x)^{3} \frac{d}{d x} (8 + 7 x)

= 4 (8 + 7 x)^{3} \frac{d}{d x} (8 + 7 x)

\frac{d}{d x} (8 + 7 x) = 7

= 4 (8 + 7 x)^{3} \cdot 7

Simplify

= 28 (8 + 7 x)^{3}

2 {d y} {d x} = \frac{21 x ^{2}}{y}

\frac{d}{d x} ((x + a) e^{2 x} + b)

\int 7 16 - 2 x d x

4 x, x^{2} - 5, [- 2.2, 0]

\int 30 x (x + 1)^{4} d x

What is the derivative of (8+7x^4) ?
The derivative of (8+7x^4) is 28(8+7x)^3
What is the first derivative of (8+7x^4) ?
The first derivative of (8+7x^4) is 28(8+7x)^3