What is the sum from n=1 to infinity of sin^2(n) ?

The sum from n=1 to infinity of sin^2(n) is diverges

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sum from n=1 to infinity of sin^2(n)

n = 1 \sum \infty sin^{2} (n)

diverges

Solution steps

n = 1 \sum \infty sin^{2} (n)

Apply Series Divergence Test:

diverges

= diverges

f (x) = x, (81, 9)

3 e^{- 5 t} + 6 e^{- 3 t}

\frac{d}{d t} (\frac{4}{t ^{2}} - \frac{5}{t} - \frac{9}{5})

f (x) = x^{10}

\int_{0}^{π} 7 sin^{2} (t co) s^{4} t d t

What is the sum from n=1 to infinity of sin^2(n) ?
The sum from n=1 to infinity of sin^2(n) is diverges