What is the integral of (sin(t))/(t^2) ?

The integral of (sin(t))/(t^2) is -(sin(t))/t+\Ci(t)+C

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integral of (sin(t))/(t^2)

\int \frac{sin ( t )}{t ^{2}} d t

- \frac{sin ( t )}{t} + Ci (t) + C

Solution steps

\int \frac{sin ( t )}{t ^{2}} d t

Apply Integration By Parts

: - \frac{sin ( t )}{t} - \int - \frac{cos ( t )}{t} d t

= - \frac{sin ( t )}{t} - \int - \frac{cos ( t )}{t} d t

\int - \frac{cos ( t )}{t} d t = - Ci (t)

= - \frac{sin ( t )}{t} - (- Ci (t))

Simplify

= - \frac{sin ( t )}{t} + Ci (t)

Add a constant to the solution

= - \frac{sin ( t )}{t} + Ci (t) + C

y^{^{''}} + 6 y^{^{'}} + 9 y = \frac{- 16 e ^{- 3 t}}{t ^{2} + 1}

\frac{s + 5}{s ^{2} + 5 s + 6}

\frac{d}{d x} (\frac{x - 1}{x ^{2} + 2 x + 1})

\int \frac{2 x}{( x ^{2} + 1 )} d x

What is the integral of (sin(t))/(t^2) ?
The integral of (sin(t))/(t^2) is -(sin(t))/t+\Ci(t)+C