What is the tangent of 7/(x^2) ?

The tangent of 7/(x^2) is y=-(14)/(a_{0)^3}x+(21)/(a_{0)^2}

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tangent of 7/(x^2)

tangent of

\frac{7}{x ^{2}}

y = - \frac{14}{a _{0}^{3}} x + \frac{21}{a _{0}^{2}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{7}{a _{0}^{2}})

Find the slope of

y = \frac{7}{x ^{2}} : \frac{d y}{d x} = - \frac{14}{x ^{3}}

Compute the slope of

y = \frac{7}{x ^{2}}

x = a_{0} : m = - \frac{14}{a _{0}^{3}}

Find the line with slope m=

- \frac{14}{a _{0}^{3}}

and passing through

(a_{0}, \frac{7}{a _{0}^{2}}) : y = - \frac{14}{a _{0}^{3}} x + \frac{21}{a _{0}^{2}}

y = - \frac{14}{a _{0}^{3}} x + \frac{21}{a _{0}^{2}}

\int tan^{5} (4 x) d x

\int \frac{x}{3 x ^{2} + 8 x - 3} d x

x^{^{''}} + 3 x^{^{'}} + 2 x = 0

x + 4

\frac{d y}{d x} + \frac{6 y}{x} = x

What is the tangent of 7/(x^2) ?
The tangent of 7/(x^2) is y=-(14)/(a_{0)^3}x+(21)/(a_{0)^2}