What is the solution for (dy}{dx}=-\frac{y+1)/x ?

The solution for (dy}{dx}=-\frac{y+1)/x is y=(c_{1})/x-1

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(dy}{dx}=-\frac{y+1)/x

\frac{d y}{d x} = - \frac{y + 1}{x}

y = \frac{c _{1}}{x} - 1

Solution steps

\frac{d y}{d x} = - \frac{y + 1}{x}

Solve separable ODE:

y = \frac{c _{1}}{x} - 1

y = \frac{c _{1}}{x} - 1

f (x) = (x^{2} + 1)^{3} (x^{2} + 2)^{6}

\frac{d}{d x} (x lo g_{10} (\frac{2}{x}))

\int \frac{x ^{2} - 1}{x} d x

\int \frac{- x + 1}{x ^{2} + 1} d x

(\frac{1}{3})^{x}

What is the solution for (dy}{dx}=-\frac{y+1)/x ?
The solution for (dy}{dx}=-\frac{y+1)/x is y=(c_{1})/x-1