What is the derivative of 3x^2-y^2 ?

The derivative of 3x^2-y^2 is 6x-2y(dy)/(dx)

What is the first derivative of 3x^2-y^2 ?

The first derivative of 3x^2-y^2 is 6x-2y(dy)/(dx)

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\frac{d}{d x} (3 x^{2} - y^{2})

6 x - 2 y \frac{d y}{d x}

Solution steps

\frac{d}{d x} (3 x^{2} - y^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (y^{2})

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (y^{2}) = 2 y \frac{d y}{d x}

= 6 x - 2 y \frac{d y}{d x}

\int sec (t) sec (t) + tan (t) d t

\int_{0}^{\infty} e^{- ∣ x ∣} d x

\frac{d}{d x} ((3 x^{2} - 9)^{- 12})

y = 2^{x}

What is the derivative of 3x^2-y^2 ?
The derivative of 3x^2-y^2 is 6x-2y(dy)/(dx)
What is the first derivative of 3x^2-y^2 ?
The first derivative of 3x^2-y^2 is 6x-2y(dy)/(dx)