What is the derivative of x^4-8x^2-4 ?

The derivative of x^4-8x^2-4 is 4x^3-16x

What is the first derivative of x^4-8x^2-4 ?

The first derivative of x^4-8x^2-4 is 4x^3-16x

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\frac{d}{d x} (x^{4} - 8 x^{2} - 4)

4 x^{3} - 16 x

Solution steps

\frac{d}{d x} (x^{4} - 8 x^{2} - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (8 x^{2}) - \frac{d}{d x} (4)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (8 x^{2}) = 16 x

\frac{d}{d x} (4) = 0

= 4 x^{3} - 16 x - 0

Simplify

= 4 x^{3} - 16 x

\int \frac{x - 4}{( x + 4 ) ( x + 3 ) ^{2}} d x

\frac{d}{d x} (\frac{1}{5} x^{5} - \frac{1}{2 x ^{4}} + 3 x + 9)

y^{^{''}} + 5 y^{^{'}} - 14 y = 0

\frac{d}{d x} (\frac{x}{2 e ^{x}})

What is the derivative of x^4-8x^2-4 ?
The derivative of x^4-8x^2-4 is 4x^3-16x
What is the first derivative of x^4-8x^2-4 ?
The first derivative of x^4-8x^2-4 is 4x^3-16x