What is the sum from n=0 to infinity of 0.4^n ?

The sum from n=0 to infinity of 0.4^n is 1.66666…

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sum from n=0 to infinity of 0.4^n

n = 0 \sum \infty 0. 4^{n}

1.66666 \dots

Solution steps

n = 0 \sum \infty 0. 4^{n}

Apply Series Geometric Test:

1.66666 \dots

= 1.66666 \dots

\frac{d}{d x} (e^{- x^{2} + 7 x})

y^{^{''}} + 1.875 y^{^{'}} + 0.125 y = 0, y (0) = 2, y^{^{'}} (0) = 1

\frac{d}{d x} (4 π)

h \to 0 lim (\frac{sin ( 7 h )}{h})

\int_{0}^{4} x - 2 d x

What is the sum from n=0 to infinity of 0.4^n ?
The sum from n=0 to infinity of 0.4^n is 1.66666…