What is the derivative of (10x-2x^2(16-2x)) ?

The derivative of (10x-2x^2(16-2x)) is 12x^2-104x+160

What is the first derivative of (10x-2x^2(16-2x)) ?

The first derivative of (10x-2x^2(16-2x)) is 12x^2-104x+160

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} ((10 x - 2 x^{2}) (16 - 2 x))

12 x^{2} - 104 x + 160

Solution steps

\frac{d}{d x} ((10 x - 2 x^{2}) (16 - 2 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 10 x - 2 x^{2}, g = 16 - 2 x

= \frac{d}{d x} (10 x - 2 x^{2}) (16 - 2 x) + \frac{d}{d x} (16 - 2 x) (10 x - 2 x^{2})

\frac{d}{d x} (10 x - 2 x^{2}) = 10 - 4 x

\frac{d}{d x} (16 - 2 x) = - 2

= (10 - 4 x) (16 - 2 x) + (- 2) (10 x - 2 x^{2})

Simplify

(10 - 4 x) (16 - 2 x) + (- 2) (10 x - 2 x^{2}) : 12 x^{2} - 104 x + 160

= 12 x^{2} - 104 x + 160

y^{^{'}} + 2 x y^{2} = 0

\int \frac{π}{1.2 - 2 x} d x

\frac{d}{d x} (18 - x^{2} - x)

f (x) = 10 x - x^{2}, g (x) = 3 x

n = 1 \sum \infty \frac{( 4 ^{n + 1} )}{5 ^{n}}

What is the derivative of (10x-2x^2(16-2x)) ?
The derivative of (10x-2x^2(16-2x)) is 12x^2-104x+160
What is the first derivative of (10x-2x^2(16-2x)) ?
The first derivative of (10x-2x^2(16-2x)) is 12x^2-104x+160