What is the integral of 3z^2sin(x)-4 ?

The integral of 3z^2sin(x)-4 is -4z+z^3sin(x)+C

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integral of 3z^2sin(x)-4

\int 3 z^{2} sin (x) - 4 d z

- 4 z + z^{3} sin (x) + C

Solution steps

\int 3 z^{2} sin (x) - 4 d z

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 4 d z + \int 3 sin (x) z^{2} d z

\int 4 d z = 4 z

\int 3 sin (x) z^{2} d z = z^{3} sin (x)

= - 4 z + z^{3} sin (x)

Add a constant to the solution

= - 4 z + z^{3} sin (x) + C

f (x) = 4 x^{5 x}

y^{^{'}} + y cos (x) = 2 cos (x), y (0) = 4

\int x^{3} e^{2 x^{2}} d x

\frac{d}{d x} (e^{s i n (x) + c o s (x)})

\frac{d}{d x} ((sin (20 x))^{3})

What is the integral of 3z^2sin(x)-4 ?
The integral of 3z^2sin(x)-4 is -4z+z^3sin(x)+C