What is the derivative of (3x^2-12/(8x)) ?

The derivative of (3x^2-12/(8x)) is (3x^2+12)/(8x^2)

What is the first derivative of (3x^2-12/(8x)) ?

The first derivative of (3x^2-12/(8x)) is (3x^2+12)/(8x^2)

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\frac{d}{d x} (\frac{3 x ^{2} - 12}{8 x})

\frac{3 x ^{2} + 12}{8 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{3 x ^{2} - 12}{8 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{8} \frac{d}{d x} (\frac{3 x ^{2} - 12}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{8} \cdot \frac{\frac{d}{d x} ( 3 x ^{2} - 12 ) x - \frac{d x}{d x} ( 3 x ^{2} - 12 )}{x ^{2}}

\frac{d}{d x} (3 x^{2} - 12) = 6 x

\frac{d x}{d x} = 1

= \frac{1}{8} \cdot \frac{6 xx - 1 \cdot ( 3 x ^{2} - 12 )}{x ^{2}}

Simplify

\frac{1}{8} \cdot \frac{6 xx - 1 \cdot ( 3 x ^{2} - 12 )}{x ^{2}} : \frac{3 x ^{2} + 12}{8 x ^{2}}

= \frac{3 x ^{2} + 12}{8 x ^{2}}

\int + ln (3) e^{x} d x

\int 3 x - 1 d x

\int s e^{- s x y} d x

\frac{5 - x e ^{x}}{x + e ^{x}}

\int \frac{( 3 x ^{3} - 4 x ^{2} + 3 x )}{x ^{2} + 1} d x

What is the derivative of (3x^2-12/(8x)) ?
The derivative of (3x^2-12/(8x)) is (3x^2+12)/(8x^2)
What is the first derivative of (3x^2-12/(8x)) ?
The first derivative of (3x^2-12/(8x)) is (3x^2+12)/(8x^2)