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Popular >

f^'(x)=0.6x^{1.5}

Solution

f^{^{'}} (x) = 0.6 x^{1.5}

Solution

f (x) = 0.24 x^{2.5} + c_{1}

Solution steps

f^{'} (x) = 0.6 x^{1.5}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int 0.6 x^{1.5} d x

\int 0.6 x^{1.5} d x = 0.24 x^{2.5} + c_{1}

f (x) = 0.24 x^{2.5} + c_{1}

Popular Examples

(\partial)/(\partial x)(sqrt(x^2+y^2-4x+5))

\frac{\partial}{\partial x} (x^{2} + y^{2} - 4 x + 5)

tangent of f(x)=sqrt(3x+7),\at x=3 tangent of

f (x) = 3 x + 7, at x = 3

(x-8)*(dy)/(dx)+y=(x^2-3)

(x - 8) \cdot \frac{d y}{d x} + y = (x^{2} - 3)

(\partial)/(\partial x)((4y)/(x^3))

\frac{\partial}{\partial x} (\frac{4 y}{x ^{3}})

sum from n=0 to infinity of infinity

n = 0 \sum \infty \infty

Frequently Asked Questions (FAQ)

What is the solution for f^'(x)=0.6x^{1.5} ?
The solution for f^'(x)=0.6x^{1.5} is f(x)=0.24x^{2.5}+c_{1}