What is the solution for (dy)/(dx)=((x-1))/(y-1) ?

The solution for (dy)/(dx)=((x-1))/(y-1) is y=1+sqrt(x^2-2x+c_{1)+1},y=1-sqrt(x^2-2x+c_{1)+1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=((x-1))/(y-1)

\frac{d y}{d x} = \frac{( x - 1 )}{y - 1}

y = 1 + x^{2} - 2 x + c_{1} + 1, y = 1 - x^{2} - 2 x + c_{1} + 1

Solution steps

\frac{d y}{d x} = \frac{( x - 1 )}{y - 1}

Solve separable ODE:

y = 1 + x^{2} - 2 x + c_{1} + 1, y = 1 - x^{2} - 2 x + c_{1} + 1

y = 1 + x^{2} - 2 x + c_{1} + 1, y = 1 - x^{2} - 2 x + c_{1} + 1

\frac{d v}{d t} - \frac{4 v}{t} = 8 t^{3}

\int 1 - y d y

\frac{d}{d x} (- (x + 1))

\frac{d}{d x} (\frac{x ^{2}}{1 + 4 x})

\int_{- 1}^{3} 1 + (6 y + 2)^{2} d y

What is the solution for (dy)/(dx)=((x-1))/(y-1) ?
The solution for (dy)/(dx)=((x-1))/(y-1) is y=1+sqrt(x^2-2x+c_{1)+1},y=1-sqrt(x^2-2x+c_{1)+1}