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Popular >

2xydx-(1+y)dy=0

Solution

2 x y d x - (1 + y) d y = 0

Solution

y = W (\frac{1}{e ^{- x^{2} - c_{1}}})

Solution steps

2 x y d x - (1 + y) d y = 0

Solve separable ODE:

y = W (\frac{1}{e ^{- x^{2} - c_{1}}})

y = W (\frac{1}{e ^{- x^{2} - c_{1}}})

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Frequently Asked Questions (FAQ)

What is the solution for 2xydx-(1+y)dy=0 ?
The solution for 2xydx-(1+y)dy=0 is y=\W(1/(e^{-x^2-c_{1)}})