What is the solution for y^{''}+y=tan(t) ?

The solution for y^{''}+y=tan(t) is y=c_{1}cos(t)+c_{2}sin(t)-cos(t)ln(tan(t)+sec(t))

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y^{''}+y=tan(t)

y^{^{''}} + y = tan (t)

y = c_{1} cos (t) + c_{2} sin (t) - cos (t) ln (tan (t) + sec (t))

Solution steps

y^{''} (t) + y = tan (t)

Solve linear ODE:

y = c_{1} cos (t) + c_{2} sin (t) - cos (t) ln (tan (t) + sec (t))

y = c_{1} cos (t) + c_{2} sin (t) - cos (t) ln (tan (t) + sec (t))

- 9 x^{3}

\frac{\partial}{\partial x} (sin (y e^{10 x}))

x \to - 2 lim (12 x + 11)

\frac{12}{x}

(- 3 x^{2} - 2)^{4}

What is the solution for y^{''}+y=tan(t) ?
The solution for y^{''}+y=tan(t) is y=c_{1}cos(t)+c_{2}sin(t)-cos(t)ln(tan(t)+sec(t))