What is the derivative of \sqrt[5]{x}-5e^x ?

The derivative of \sqrt[5]{x}-5e^x is 1/(5x^{4/5)}-5e^x

What is the first derivative of \sqrt[5]{x}-5e^x ?

The first derivative of \sqrt[5]{x}-5e^x is 1/(5x^{4/5)}-5e^x

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\frac{1}{5 x ^{\frac{4}{5}}} - 5 e^{x}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (5 e^{x}) = 5 e^{x}

= \frac{1}{5 x ^{\frac{4}{5}}} - 5 e^{x}

x^{(\frac{1}{3})}, 8

\int 2 x x^{2} + 4 d x

\int \frac{1}{x ^{2} + 81} d x

\int_{1}^{x} 1 + 2 t d t

\frac{d}{d x} (\frac{4}{3} \cdot π \cdot x^{3})

What is the derivative of \sqrt[5]{x}-5e^x ?
The derivative of \sqrt[5]{x}-5e^x is 1/(5x^{4/5)}-5e^x
What is the first derivative of \sqrt[5]{x}-5e^x ?
The first derivative of \sqrt[5]{x}-5e^x is 1/(5x^{4/5)}-5e^x