What is the derivative of 5tsin(pit) ?

The derivative of 5tsin(pit) is 5(sin(pit)+pitcos(pit))

What is the first derivative of 5tsin(pit) ?

The first derivative of 5tsin(pit) is 5(sin(pit)+pitcos(pit))

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derivative of

5 t sin (π t)

5 (sin (π t) + π t cos (π t))

Solution steps

\frac{d}{d t} (5 t sin (π t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d t} (t sin (π t))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = t, g = sin (π t)

= 5 (\frac{d t}{d t} sin (π t) + \frac{d}{d t} (sin (π t)) t)

\frac{d t}{d t} = 1

\frac{d}{d t} (sin (π t)) = cos (π t) π

= 5 (1 \cdot sin (π t) + cos (π t) π t)

Simplify

= 5 (sin (π t) + π t cos (π t))

y = e^{2 x}, y = e^{3 x}, x = 1

x \to - 6 lim (- 5 x - 6)

f (x) = \frac{2 x}{x ^{2} - 7}, at x = 3

\int \frac{sin ( 3 x )}{3 cos ( 3 x )} d x

\int x^{2} e^{15 x} d x

What is the derivative of 5tsin(pit) ?
The derivative of 5tsin(pit) is 5(sin(pit)+pitcos(pit))
What is the first derivative of 5tsin(pit) ?
The first derivative of 5tsin(pit) is 5(sin(pit)+pitcos(pit))