What is the limit as x approaches infinity of xe^{-x} ?

The limit as x approaches infinity of xe^{-x} is 0

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limit as x approaches infinity of xe^{-x}

x \to \infty lim (x e^{- x})

0

Solution steps

x \to \infty lim (x e^{- x})

Rewrite for L'Hopital

= x \to \infty lim (\frac{x}{\frac{1}{e ^{- x}}})

Apply L'Hopital's Rule

: x \to \infty lim (\frac{1}{e ^{x}})

= x \to \infty lim (\frac{1}{e ^{x}})

x \to a lim [\frac{f ( x )}{g ( x )}] = \frac{lim _{x \to a} f ( x )}{lim _{x \to a} g ( x )}, x \to a lim g (x) \neq = 0

With the exception of indeterminate form

= \frac{lim _{x \to \infty} ( 1 )}{lim _{x \to \infty} ( e ^{x} )}

x \to \infty lim (1) = 1

x \to \infty lim (e^{x}) = \infty

= \frac{1}{\infty}

Apply Infinity Property:

\frac{c}{\infty} = 0

= 0

\frac{d}{d x} (tan (0))

\frac{\partial}{\partial x} (y^{3})

in (sin (x))

\frac{d}{d x} (\frac{1}{csc ^{2} ( x )})

\int \frac{1}{2 x ^{2} + 8 x + 25} d x

What is the limit as x approaches infinity of xe^{-x} ?
The limit as x approaches infinity of xe^{-x} is 0