What is (\partial)/(\partial x)((x^2-1)/(x+1)) ?

The answer to (\partial)/(\partial x)((x^2-1)/(x+1)) is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)((x^2-1)/(x+1))

\frac{\partial}{\partial x} (\frac{x ^{2} - 1}{x + 1})

1

Solution steps

\frac{\partial}{\partial x} (\frac{x ^{2} - 1}{x + 1})

Simplify

\frac{x ^{2} - 1}{x + 1} : x - 1

= \frac{\partial}{\partial x} (x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (1) = 0

= 1 - 0

Simplify

= 1

y^{^{''}} + 2 y^{^{'}} + y = \frac{- 18.5 e ^{- t}}{t ^{2} + 1}

\int cos (3 x) sin (3 x) d x

\frac{\partial}{\partial x} (7 + ln (x y - 9))

\frac{d}{d x} (e^{a x^{9}})

\frac{d}{d y} (e^{x} cos (y))

What is (\partial)/(\partial x)((x^2-1)/(x+1)) ?
The answer to (\partial)/(\partial x)((x^2-1)/(x+1)) is 1