What is the derivative of y=ln(x^8) ?

The derivative of y=ln(x^8) is 8/x

What is the first derivative of y=ln(x^8) ?

The first derivative of y=ln(x^8) is 8/x

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derivative of

y = ln (x^{8})

\frac{8}{x}

Solution steps

\frac{d}{d x} (ln (x^{8}))

Apply the chain rule:

\frac{1}{x ^{8}} \frac{d}{d x} (x^{8})

= \frac{1}{x ^{8}} \frac{d}{d x} (x^{8})

\frac{d}{d x} (x^{8}) = 8 x^{7}

= \frac{1}{x ^{8}} \cdot 8 x^{7}

Simplify

\frac{1}{x ^{8}} \cdot 8 x^{7} : \frac{8}{x}

= \frac{8}{x}

\int - csc^{2} (\frac{8 x}{5}) d x

\frac{d y}{d x} = x^{5} (y - 3), y (0) = 5

\int (x + 1) (x + 2)^{6} d x

\int 5 x^{4} - 4 x^{5} d x

35 + 35 sin (\frac{- 2 π t - π}{2})

What is the derivative of y=ln(x^8) ?
The derivative of y=ln(x^8) is 8/x
What is the first derivative of y=ln(x^8) ?
The first derivative of y=ln(x^8) is 8/x