What is (\partial)/(\partial x)(4x-4x^3) ?

The answer to (\partial)/(\partial x)(4x-4x^3) is 4-12x^2

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(\partial)/(\partial x)(4x-4x^3)

\frac{\partial}{\partial x} (4 x - 4 x^{3})

4 - 12 x^{2}

Solution steps

\frac{\partial}{\partial x} (4 x - 4 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4 x) - \frac{\partial}{\partial x} (4 x^{3})

\frac{\partial}{\partial x} (4 x) = 4

\frac{\partial}{\partial x} (4 x^{3}) = 12 x^{2}

= 4 - 12 x^{2}

\int (\frac{1}{( x - 1 ) ^{2}}) d x

y^{^{''}} + 9 y = cos (2 t)

h \to 0 lim (\frac{( ( 4 + h ) - 4 )}{h})

\frac{d}{d x} (a x e^{4 x})

\int \frac{x ^{2}}{( x - 1 ) ( x + 1 )} d x

What is (\partial)/(\partial x)(4x-4x^3) ?
The answer to (\partial)/(\partial x)(4x-4x^3) is 4-12x^2