What is the solution for (dy}{dx}=\frac{(x-2))/x ?

The solution for (dy}{dx}=\frac{(x-2))/x is y=x-2ln(x)+c_{1}

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(dy}{dx}=\frac{(x-2))/x

\frac{d y}{d x} = \frac{( x - 2 )}{x}

y = x - 2 ln (x) + c_{1}

Solution steps

\frac{d y}{d x} = \frac{( x - 2 )}{x}

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = \frac{( x - 2 )}{x}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int \frac{x - 2}{x} d x

\int \frac{x - 2}{x} d x = x - 2 ln (x) + c_{1}

y = x - 2 ln (x) + c_{1}

(2 x^{2} + x + 1)^{- 3}

\frac{d a}{d a}

\frac{d y}{d t} = \frac{( 2 y ^{4} + t ^{4} )}{t y ^{3}}

\frac{d y}{d t} + 20 \frac{6}{5} - \frac{6}{5} e^{- 20 t} = 24

\int \frac{tan ^{2} ( x )}{sec ( x )} d x

What is the solution for (dy}{dx}=\frac{(x-2))/x ?
The solution for (dy}{dx}=\frac{(x-2))/x is y=x-2ln(x)+c_{1}