What is the solution for y^'+4y^2e^{-1x}=0,y(0)=3 ?

The solution for y^'+4y^2e^{-1x}=0,y(0)=3 is y=-(3e^x)/(12-13e^x)

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y^'+4y^2e^{-1x}=0,y(0)=3

y^{^{'}} + 4 y^{2} e^{- 1 x} = 0, y (0) = 3

y = - \frac{3 e ^{x}}{12 - 13 e ^{x}}

Solution steps

y^{'} (x) + 4 y^{2} e^{- 1 x} = 0

Solve separable ODE:

y = - \frac{3 e ^{x}}{12 - 13 e ^{x}}

y = - \frac{3 e ^{x}}{12 - 13 e ^{x}}

e^{3 t} cos (3 t)

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\int (5 x^{2} - 4 x) e^{2 x} d x

\int_{\frac{1}{2}}^{4} \frac{2}{x} - \frac{1}{8} x d x

\frac{d}{d x} (\frac{2 x}{e ^{x}})

What is the solution for y^'+4y^2e^{-1x}=0,y(0)=3 ?
The solution for y^'+4y^2e^{-1x}=0,y(0)=3 is y=-(3e^x)/(12-13e^x)