What is laplacetransform cos(15t) ?

The answer to laplacetransform cos(15t) is s/(s^2+225)

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laplacetransform cos(15t)

laplace transform

cos (15 t)

\frac{s}{s ^{2} + 225}

Solution steps

L {cos (15 t)}

Use Laplace Transform table:

L {cos (a t)} = \frac{s}{s ^{2} + a ^{2}}

L {cos (15 t)} = \frac{s}{s ^{2} + 1 5 ^{2}}

= \frac{s}{s ^{2} + 1 5 ^{2}}

= \frac{s}{s ^{2} + 225}

\frac{d}{d x} (\frac{2 x}{2 + x ^{2}})

y^{^{''}} + 5 y^{^{'}} + 6 y = 0, y (0) = 2, y^{^{'}} (0) = 0

\frac{\frac{1}{s + 1} - 1}{s ^{2} - 1}

\int z^{2} (\frac{1}{2 π} e^{- \frac{1}{2} z^{2}}) d z

\int 3 sin^{2} (x) d x

What is laplacetransform cos(15t) ?
The answer to laplacetransform cos(15t) is s/(s^2+225)