What is the integral of (\sqrt[4]{x^3}-2/(\sqrt[3]{x^2)}) ?

The integral of (\sqrt[4]{x^3}-2/(\sqrt[3]{x^2)}) is 4/7 x^{7/4}-6\sqrt[3]{x}+C

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integral of (\sqrt[4]{x^3}-2/(\sqrt[3]{x^2)})

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

Add a constant to the solution

\frac{\partial}{\partial y} (x^{y} + ln (z))

\frac{d y}{d t} - 5 y = sin (2 t)

y = 47 (2 t^{3} - 9)^{\frac{6}{5}}

\int \frac{3}{5 y - 4} d y

x \to 0 lim (\frac{6 x n - 5 x n - 1 - 7 x n - 2}{- 6 x n - 4 x n - 2})

What is the integral of (\sqrt[4]{x^3}-2/(\sqrt[3]{x^2)}) ?
The integral of (\sqrt[4]{x^3}-2/(\sqrt[3]{x^2)}) is 4/7 x^{7/4}-6\sqrt[3]{x}+C