What is the derivative of f(x)=(x^4+3x^2-2)^5 ?

The derivative of f(x)=(x^4+3x^2-2)^5 is 5(x^4+3x^2-2)^4(4x^3+6x)

What is the first derivative of f(x)=(x^4+3x^2-2)^5 ?

The first derivative of f(x)=(x^4+3x^2-2)^5 is 5(x^4+3x^2-2)^4(4x^3+6x)

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derivative of

f (x) = (x^{4} + 3 x^{2} - 2)^{5}

5 (x^{4} + 3 x^{2} - 2)^{4} (4 x^{3} + 6 x)

Solution steps

\frac{d}{d x} ((x^{4} + 3 x^{2} - 2)^{5})

Apply the chain rule:

5 (x^{4} + 3 x^{2} - 2)^{4} \frac{d}{d x} (x^{4} + 3 x^{2} - 2)

= 5 (x^{4} + 3 x^{2} - 2)^{4} \frac{d}{d x} (x^{4} + 3 x^{2} - 2)

\frac{d}{d x} (x^{4} + 3 x^{2} - 2) = 4 x^{3} + 6 x

= 5 (x^{4} + 3 x^{2} - 2)^{4} (4 x^{3} + 6 x)

ln (s + 1)

\int \frac{3 - x}{x - 4} d x

(0, 2), (4, - 1)

\int \frac{sin ^{7} ( 2 x )}{cos ^{4} ( 2 x )} d x

\frac{\partial}{\partial x} (x y^{3} z^{2})

What is the derivative of f(x)=(x^4+3x^2-2)^5 ?
The derivative of f(x)=(x^4+3x^2-2)^5 is 5(x^4+3x^2-2)^4(4x^3+6x)
What is the first derivative of f(x)=(x^4+3x^2-2)^5 ?
The first derivative of f(x)=(x^4+3x^2-2)^5 is 5(x^4+3x^2-2)^4(4x^3+6x)