What is the derivative of y=sec(x^2+3x) ?

The derivative of y=sec(x^2+3x) is sec(x^2+3x)tan(x^2+3x)(2x+3)

What is the first derivative of y=sec(x^2+3x) ?

The first derivative of y=sec(x^2+3x) is sec(x^2+3x)tan(x^2+3x)(2x+3)

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derivative of

y = sec (x^{2} + 3 x)

sec (x^{2} + 3 x) tan (x^{2} + 3 x) (2 x + 3)

Solution steps

\frac{d}{d x} (sec (x^{2} + 3 x))

Apply the chain rule:

sec (x^{2} + 3 x) tan (x^{2} + 3 x) \frac{d}{d x} (x^{2} + 3 x)

= sec (x^{2} + 3 x) tan (x^{2} + 3 x) \frac{d}{d x} (x^{2} + 3 x)

\frac{d}{d x} (x^{2} + 3 x) = 2 x + 3

= sec (x^{2} + 3 x) tan (x^{2} + 3 x) (2 x + 3)

\int 2 x (x^{2} - 7)^{104} d x

\frac{d}{d x} (15 ln (x) + 4 cos (x) + o)

\frac{d}{d x} ((4 x^{2} - 3 x) (2 x + 1))

f (x) = 2 x^{2} cos (4 x)

n = 1 \sum \infty \frac{n}{2 n - 1}

What is the derivative of y=sec(x^2+3x) ?
The derivative of y=sec(x^2+3x) is sec(x^2+3x)tan(x^2+3x)(2x+3)
What is the first derivative of y=sec(x^2+3x) ?
The first derivative of y=sec(x^2+3x) is sec(x^2+3x)tan(x^2+3x)(2x+3)