What is the solution for (dy)/(dx)-4/x y=2x^5e^{y/(x^4)} ?

The solution for (dy)/(dx)-4/x y=2x^5e^{y/(x^4)} is y=-x^4ln(-x^2-c_{1})

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(dy)/(dx)-4/x y=2x^5e^{y/(x^4)}

\frac{d y}{d x} - \frac{4}{x} y = 2 x^{5} e^{\frac{y}{x ^{4}}}

y = - x^{4} ln (- x^{2} - c_{1})

Solution steps

\frac{d y}{d x} - \frac{4}{x} y = 2 x^{5} e^{\frac{y}{x ^{4}}}

Solve using substitution:

y = - x^{4} ln (- x^{2} - c_{1})

y = - x^{4} ln (- x^{2} - c_{1})

y^{2} = x + 6, y^{2} = 6 - x

\int - 3 x + 2 x d x

n = 0 \sum \infty (2 x + 5)^{n}

5 x^{2} - x^{3}

x \to 0 lim (ln (1 - 7 x))

What is the solution for (dy)/(dx)-4/x y=2x^5e^{y/(x^4)} ?
The solution for (dy)/(dx)-4/x y=2x^5e^{y/(x^4)} is y=-x^4ln(-x^2-c_{1})