What is the integral of (cos(θ))/(sin^2(θ)) ?

The integral of (cos(θ))/(sin^2(θ)) is -csc(θ)+C

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integral of (cos(θ))/(sin^2(θ))

\int \frac{cos ( θ )}{sin ^{2} ( θ )} d θ

- csc (θ) + C

Solution steps

\int \frac{cos ( θ )}{sin ^{2} ( θ )} d θ

Apply u-substitution

: \int \frac{1}{u ^{2}} d u

= \int \frac{1}{u ^{2}} d u

Apply the Power Rule

: - \frac{1}{u}

= - \frac{1}{u}

Substitute back

u = sin (θ)

= - \frac{1}{sin ( θ )}

Use the basic trigonometric identity:

\frac{1}{sin ( x )} = csc (x)

= - csc (θ)

Add a constant to the solution

= - csc (θ) + C

\frac{\partial}{\partial x} (\frac{2 x - 2 y}{y ^{2} + 4 x ^{2}})

\int x^{2} sin (a x) d x

\frac{9}{r ^{3}}

y = x^{2} + 5 x, y = 3 - x^{2}

f (x) = x + 2

What is the integral of (cos(θ))/(sin^2(θ)) ?
The integral of (cos(θ))/(sin^2(θ)) is -csc(θ)+C