What is the derivative of 1/(9x^2) ?

The derivative of 1/(9x^2) is -2/(9x^3)

What is the first derivative of 1/(9x^2) ?

The first derivative of 1/(9x^2) is -2/(9x^3)

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derivative of

\frac{1}{9 x ^{2}}

- \frac{2}{9 x ^{3}}

Solution steps

\frac{d}{d x} (\frac{1}{9 x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{9} \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{9} \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{9} (- 2 x^{- 2 - 1})

Simplify

\frac{1}{9} (- 2 x^{- 2 - 1}) : - \frac{2}{9 x ^{3}}

= - \frac{2}{9 x ^{3}}

(x^{3} + 2 x + 7) (2 + \frac{1}{x ^{2}})

x^{4} - 18 x^{2} + 81

\int \frac{x ^{2}}{y} d x

\frac{d y}{d x} = (3 e x - 9 e - x)^{2}

\int_{1}^{2} \frac{7}{x ^{2}} d x

What is the derivative of 1/(9x^2) ?
The derivative of 1/(9x^2) is -2/(9x^3)
What is the first derivative of 1/(9x^2) ?
The first derivative of 1/(9x^2) is -2/(9x^3)