What is the derivative of 4x^3-5x^2+ln(x) ?

The derivative of 4x^3-5x^2+ln(x) is 12x^2-10x+1/x

What is the first derivative of 4x^3-5x^2+ln(x) ?

The first derivative of 4x^3-5x^2+ln(x) is 12x^2-10x+1/x

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\frac{d}{d x} (4 x^{3} - 5 x^{2} + ln (x))

12 x^{2} - 10 x + \frac{1}{x}

Solution steps

\frac{d}{d x} (4 x^{3} - 5 x^{2} + ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) - \frac{d}{d x} (5 x^{2}) + \frac{d}{d x} (ln (x))

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (5 x^{2}) = 10 x

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 12 x^{2} - 10 x + \frac{1}{x}

y^{2} - 2 x = 1, x - y = 1

cos (t) + t^{2} sin (t)

f (x) = arctan (\frac{x}{a})

\frac{d}{d x} (cosh^{3} (x))

\int (10 x + 6) d x

What is the derivative of 4x^3-5x^2+ln(x) ?
The derivative of 4x^3-5x^2+ln(x) is 12x^2-10x+1/x
What is the first derivative of 4x^3-5x^2+ln(x) ?
The first derivative of 4x^3-5x^2+ln(x) is 12x^2-10x+1/x