What is the derivative of sqrt(6-9x) ?

The derivative of sqrt(6-9x) is -9/(2sqrt(6-9x))

What is the first derivative of sqrt(6-9x) ?

The first derivative of sqrt(6-9x) is -9/(2sqrt(6-9x))

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\frac{d}{d x} (6 - 9 x)

- \frac{9}{2 6 - 9 x}

Solution steps

\frac{d}{d x} (6 - 9 x)

Apply the chain rule:

\frac{1}{2 6 - 9 x} \frac{d}{d x} (6 - 9 x)

= \frac{1}{2 6 - 9 x} \frac{d}{d x} (6 - 9 x)

\frac{d}{d x} (6 - 9 x) = - 9

= \frac{1}{2 6 - 9 x} (- 9)

Simplify

\frac{1}{2 6 - 9 x} (- 9) : - \frac{9}{2 6 - 9 x}

= - \frac{9}{2 6 - 9 x}

f (x) = e^{4 x} cos (7 x)

sin (4 t + 5)

f (x) = - x^{3}, (- 2, 8)

\int cos (x^{2}) 2 x d x

n = 1 \sum \infty \frac{1}{n} - \frac{1}{n + 1}

What is the derivative of sqrt(6-9x) ?
The derivative of sqrt(6-9x) is -9/(2sqrt(6-9x))
What is the first derivative of sqrt(6-9x) ?
The first derivative of sqrt(6-9x) is -9/(2sqrt(6-9x))