What is area x=sqrt(1/(12y)),y=x,x=16y ?

The answer to area x=sqrt(1/(12y)),y=x,x=16y is (-\sqrt[3]{6}+2\sqrt[3]{3}*2^{2/3})/(16)

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area x=sqrt(1/(12y)),y=x,x=16y

area

x = \frac{1}{12 y}, y = x, x = 16 y

Decimal Notation

0.17260 \dots

Solution steps

Isolate

y

for

x = \frac{1}{12 y} : y = \frac{1}{12 x ^{2}}

Isolate

y

for

x = 16 y : y = \frac{x}{16}

f_{1} (x) = \frac{1}{12 x ^{2}}

f_{2} (x) = x

To find the intersection points solve

f_{i} (x) = f_{j} (x)

x = \frac{x}{16} : x = 0

Simplify

\frac{\partial}{\partial x} (- (\frac{x}{y}))

\frac{d}{d x} (\frac{x}{4 - 16 - x ^{2}})

f (x) = 5 - 2 x^{2}, (- 5, - 45)

\int_{0}^{2} (1 + x)^{\frac{1}{3}} \cdot 2 d x

x y^{'} + (1 + x \cdot cot (x)) y = 0

What is area x=sqrt(1/(12y)),y=x,x=16y ?
The answer to area x=sqrt(1/(12y)),y=x,x=16y is (-\sqrt[3]{6}+2\sqrt[3]{3}*2^{2/3})/(16)