What is the derivative of 5/(2x^3) ?

The derivative of 5/(2x^3) is -(15)/(2x^4)

What is the first derivative of 5/(2x^3) ?

The first derivative of 5/(2x^3) is -(15)/(2x^4)

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derivative of

\frac{5}{2 x ^{3}}

- \frac{15}{2 x ^{4}}

Solution steps

\frac{d}{d x} (\frac{5}{2 x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{5}{2} \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{5}{2} \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{5}{2} (- 3 x^{- 3 - 1})

Simplify

\frac{5}{2} (- 3 x^{- 3 - 1}) : - \frac{15}{2 x ^{4}}

= - \frac{15}{2 x ^{4}}

w \to 0 lim (\frac{sec ( 2 w ) - 1}{w sec ( 2 w )})

y = x, y = 8 - x, y = 0

2 sin (x) + 2 cos (x)

y^{^{'}} = y^{2} sin (x^{2}), y (- 2) = \frac{1}{3}

x \to 0 lim (g (x) (f (x)))

What is the derivative of 5/(2x^3) ?
The derivative of 5/(2x^3) is -(15)/(2x^4)
What is the first derivative of 5/(2x^3) ?
The first derivative of 5/(2x^3) is -(15)/(2x^4)