What is the integral from 0 to 1 of (e^x)/x ?

The integral from 0 to 1 of (e^x)/x is \Ei(1)-\Ei(0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of (e^x)/x

\int_{0}^{1} \frac{e ^{x}}{x} d x

Ei (1) - Ei (0)

Solution steps

\int_{0}^{1} \frac{e ^{x}}{x} d x

Use the nonelementary integral:

\int \frac{e ^{x}}{x} d x = Ei (x)

= [Ei (x)]_{0}^{1}

Compute the boundaries:

Ei (1) - Ei (0)

= Ei (1) - Ei (0)

\frac{d}{d x} (\frac{x ^{2} + 40 x}{5})

f (x) = 2 + x - x^{2}, 0, 3

h \to 0 lim (8 x + 4 h + 9)

\frac{d}{d x} (x^{3} - 3 x - x)

\int \frac{1}{3 + 2 cos ( x ) + 3 sin ( x )} d x

What is the integral from 0 to 1 of (e^x)/x ?
The integral from 0 to 1 of (e^x)/x is \Ei(1)-\Ei(0)