What is the slope of 2x^2+10x-4/(x^2),\at x=-5 ?

The slope of 2x^2+10x-4/(x^2),\at x=-5 is -1258/125

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slope of 2x^2+10x-4/(x^2),\at x=-5

slope

2 x^{2} + 10 x - \frac{4}{x ^{2}}, at x = - 5

- \frac{1258}{125}

Solution steps

y = 2 x^{2} + 10 x - \frac{4}{x ^{2}}

In order to find the slope of the function, take the derivative of

2 x^{2} + 10 x - \frac{4}{x ^{2}}

\frac{d}{d x} (2 x^{2} + 10 x - \frac{4}{x ^{2}}) = 4 x + 10 + \frac{8}{x ^{3}}

4 x + 10 + \frac{8}{x ^{3}}

Find the value of

4 x + 10 + \frac{8}{x ^{3}}

for

x = - 5 : - \frac{1258}{125}

- \frac{1258}{125}

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What is the slope of 2x^2+10x-4/(x^2),\at x=-5 ?
The slope of 2x^2+10x-4/(x^2),\at x=-5 is -1258/125