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Popular >

y^'-e^{x+1}=0

Solution

y^{^{'}} - e^{x + 1} = 0

Solution

y = e^{1 + x} + c_{1}

Solution steps

y^{'} (x) - e^{x + 1} = 0

Isolate

y^{'} (x) : y^{'} (x) = e^{x + 1}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int e^{x + 1} d x

\int e^{x + 1} d x = e^{1 + x} + c_{1}

y = e^{1 + x} + c_{1}

Popular Examples

integral of sec(x/4)

\int sec (\frac{x}{4}) d x

y^{''}+9y=2sin(x)+cos(x)

y^{^{''}} + 9 y = 2 sin (x) + cos (x)

\frac{d y}{d x} - x y = x

25y^{''}+90y^'+81y=0

25 y^{^{''}} + 90 y^{^{'}} + 81 y = 0

derivative of 656112^{sqrt(x)}

\frac{d}{d x} (65611 2^{x})

Frequently Asked Questions (FAQ)

What is the solution for y^'-e^{x+1}=0 ?
The solution for y^'-e^{x+1}=0 is y=e^{1+x}+c_{1}