What is the derivative of 8x^2e^x ?

The derivative of 8x^2e^x is 8(2xe^x+e^xx^2)

What is the first derivative of 8x^2e^x ?

The first derivative of 8x^2e^x is 8(2xe^x+e^xx^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

8 x^{2} e^{x}

8 (2 x e^{x} + e^{x} x^{2})

Solution steps

\frac{d}{d x} (8 x^{2} e^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (x^{2} e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = e^{x}

= 8 (\frac{d}{d x} (x^{2}) e^{x} + \frac{d}{d x} (e^{x}) x^{2})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (e^{x}) = e^{x}

= 8 (2 x e^{x} + e^{x} x^{2})

\frac{d}{d x} (1 - 121 x^{2} arccos (11 x))

\frac{s}{s ^{2} + 64}

\int (x^{3} - 4 x - 6) d x

\frac{d}{d x} ((3 x^{2} + 2) (2 x - 3))

\int \frac{7 x ^{2}}{( 9 + x ^{2} ) ^{2}} d x

What is the derivative of 8x^2e^x ?
The derivative of 8x^2e^x is 8(2xe^x+e^xx^2)
What is the first derivative of 8x^2e^x ?
The first derivative of 8x^2e^x is 8(2xe^x+e^xx^2)