What is the derivative of x^2-4x-5 ?

The derivative of x^2-4x-5 is 2x-4

What is the first derivative of x^2-4x-5 ?

The first derivative of x^2-4x-5 is 2x-4

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\frac{d}{d x} (x^{2} - 4 x - 5)

2 x - 4

Solution steps

\frac{d}{d x} (x^{2} - 4 x - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4 x) - \frac{d}{d x} (5)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (5) = 0

= 2 x - 4 - 0

Simplify

= 2 x - 4

n = 1 \sum \infty \frac{1}{n \cdot ( n + 1 )}

\int \frac{1 + x}{- x x} d x

\int_{0}^{1} - (x^{2} - x) d x

x \to 3 lim (- 7 - x)

\int x e^{2 x} d x

What is the derivative of x^2-4x-5 ?
The derivative of x^2-4x-5 is 2x-4
What is the first derivative of x^2-4x-5 ?
The first derivative of x^2-4x-5 is 2x-4