What is taylor 1/(2x+2) ?

The answer to taylor 1/(2x+2) is 1/2-1/2 x+1/2 x^2-1/2 x^3+1/2 x^4+\ldots

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taylor 1/(2x+2)

taylor

\frac{1}{2 x + 2}

\frac{1}{2} - \frac{1}{2} x + \frac{1}{2} x^{2} - \frac{1}{2} x^{3} + \frac{1}{2} x^{4} + \dots

Solution steps

Apply the Taylor Formula

= \frac{1}{2} + \frac{\frac{d}{d x} ( \frac{1}{2 x + 2} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( \frac{1}{2 x + 2} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( \frac{1}{2 x + 2} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= \frac{1}{2} + \frac{- \frac{1}{2}}{1 !} x + \frac{1}{2 !} x^{2} + \frac{- 3}{3 !} x^{3} + \frac{12}{4 !} x^{4} + \dots

Refine

= \frac{1}{2} - \frac{1}{2} x + \frac{1}{2} x^{2} - \frac{1}{2} x^{3} + \frac{1}{2} x^{4} + \dots

\frac{d}{d x} (\frac{ln ( 7 x )}{7 x})

\int_{0}^{\infty} e^{- x} x^{2} d x

y^{^{'}} = 0.0016 y (2800 - y)

\int \frac{( x - 5 )}{x ^{2} - 18 x + 82} d x

f (x) = 1.5 x^{2} + 2 x^{1.5}

What is taylor 1/(2x+2) ?
The answer to taylor 1/(2x+2) is 1/2-1/2 x+1/2 x^2-1/2 x^3+1/2 x^4+\ldots