What is the sum from n=1 to infinity of 1/(n^4+n^2) ?

The sum from n=1 to infinity of 1/(n^4+n^2) is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of 1/(n^4+n^2)

n = 1 \sum \infty \frac{1}{n ^{4} + n ^{2}}

converges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{4} + n ^{2}}

Apply Series Comparison Test:

converges

= converges

\frac{d}{d x} (\frac{x ^{2} - 3 x - 4}{x + 1})

x \to \infty lim (\frac{3}{2 x})

\frac{d}{d x} (a x + \frac{a}{a x})

\frac{d}{d x} (44 (2 x^{3} - 5)^{\frac{6}{5}})

\frac{d}{d x} (x^{3} os (x))

What is the sum from n=1 to infinity of 1/(n^4+n^2) ?
The sum from n=1 to infinity of 1/(n^4+n^2) is converges