What is the derivative of f(x)=ln(3xe^{-x}) ?

The derivative of f(x)=ln(3xe^{-x}) is 1/x-1

What is the first derivative of f(x)=ln(3xe^{-x}) ?

The first derivative of f(x)=ln(3xe^{-x}) is 1/x-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = ln (3 x e^{- x})

\frac{1}{x} - 1

Solution steps

\frac{d}{d x} (ln (3 x e^{- x}))

Simplify

ln (3 x e^{- x}) : ln (3 x) - x

= \frac{d}{d x} (ln (3 x) - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (ln (3 x)) - \frac{d x}{d x}

\frac{d}{d x} (ln (3 x)) = \frac{1}{x}

\frac{d x}{d x} = 1

= \frac{1}{x} - 1

\frac{f ( x )}{x ^{5}}

\frac{\partial}{\partial x} (sin (x^{2} + y^{3}))

\int - \frac{1}{4 - x} d x

(x^{2} + 4) sin (5 x)

θ \to 0 + lim (\frac{s}{d})

What is the derivative of f(x)=ln(3xe^{-x}) ?
The derivative of f(x)=ln(3xe^{-x}) is 1/x-1
What is the first derivative of f(x)=ln(3xe^{-x}) ?
The first derivative of f(x)=ln(3xe^{-x}) is 1/x-1