What is the derivative of 1-e^{-x/2} ?

The derivative of 1-e^{-x/2} is 1/2 e^{-x/2}

What is the first derivative of 1-e^{-x/2} ?

The first derivative of 1-e^{-x/2} is 1/2 e^{-x/2}

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\frac{d}{d x} (1 - e^{- \frac{x}{2}})

\frac{1}{2} e^{- \frac{x}{2}}

Solution steps

\frac{d}{d x} (1 - e^{- \frac{x}{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (e^{- \frac{x}{2}})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (e^{- \frac{x}{2}}) = - \frac{1}{2} e^{- \frac{x}{2}}

= 0 - (- \frac{1}{2} e^{- \frac{x}{2}})

Simplify

= \frac{1}{2} e^{- \frac{x}{2}}

\frac{1}{x - 5}

\frac{d}{d x} ((3 x + 2)^{3})

\int_{0}^{1} 5 ln (x) d x

f (x) = x \cdot e^{- x + 1}

\int_{1}^{e} \frac{1}{x ( x ^{2} + 1 )} d x

What is the derivative of 1-e^{-x/2} ?
The derivative of 1-e^{-x/2} is 1/2 e^{-x/2}
What is the first derivative of 1-e^{-x/2} ?
The first derivative of 1-e^{-x/2} is 1/2 e^{-x/2}