What is the derivative of e^x-x^3-7 ?

The derivative of e^x-x^3-7 is -3x^2+e^x

What is the first derivative of e^x-x^3-7 ?

The first derivative of e^x-x^3-7 is -3x^2+e^x

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\frac{d}{d x} (e^{x} - x^{3} - 7)

- 3 x^{2} + e^{x}

Solution steps

\frac{d}{d x} (e^{x} - x^{3} - 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) - \frac{d}{d x} (x^{3}) - \frac{d}{d x} (7)

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (7) = 0

= e^{x} - 3 x^{2} - 0

Simplify

= - 3 x^{2} + e^{x}

\frac{d}{d x} (60 x^{2})

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\int (cos (x) + \frac{1}{6} x) d x

\int - \frac{x ^{3}}{1 - x ^{2}} d x

What is the derivative of e^x-x^3-7 ?
The derivative of e^x-x^3-7 is -3x^2+e^x
What is the first derivative of e^x-x^3-7 ?
The first derivative of e^x-x^3-7 is -3x^2+e^x