What is the limit as x approaches 0 of (x^3-8)/(x+2) ?

The limit as x approaches 0 of (x^3-8)/(x+2) is -4

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limit as x approaches 0 of (x^3-8)/(x+2)

x \to 0 lim (\frac{x ^{3} - 8}{x + 2})

- 4

Solution steps

x \to 0 lim (\frac{x ^{3} - 8}{x + 2})

Plug in the value

x = 0

= \frac{0 ^{3} - 8}{0 + 2}

Simplify

\frac{0 ^{3} - 8}{0 + 2} : - 4

= - 4

\frac{d}{d t} (sin (4 t))

f (x) = e - 1

- \frac{y}{x ^{2}} d x + \frac{1}{x} d y = 0

h (x) = (x - 4) (\frac{x}{2} + 1)^{3}

x \to 3 + lim (\frac{x + 1}{x ^{2} - 9})

What is the limit as x approaches 0 of (x^3-8)/(x+2) ?
The limit as x approaches 0 of (x^3-8)/(x+2) is -4