What is the integral of (8x-10y+2) ?

The integral of (8x-10y+2) is 2y-5y^2+8xy+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (8x-10y+2)

\int (8 x - 10 y + 2) d y

2 y - 5 y^{2} + 8 x y + C

Solution steps

\int 8 x - 10 y + 2 d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 d y - \int 10 y d y + \int 8 x d y

\int 2 d y = 2 y

\int 10 y d y = 5 y^{2}

\int 8 x d y = 8 x y

= 2 y - 5 y^{2} + 8 x y

Add a constant to the solution

= 2 y - 5 y^{2} + 8 x y + C

y^{^{''}} + 2 y^{^{'}} + 2 y = 0

\frac{d}{d x} (e^{l n (s i n (x^{2}))} 2 x + 1)

\frac{d}{d x} (e x^{2})

\frac{d}{d x} (x^{3} + 2 x^{2} - 4 x + 5)

\frac{\partial}{\partial y} (\frac{x}{x ^{6} - y ^{4}})

What is the integral of (8x-10y+2) ?
The integral of (8x-10y+2) is 2y-5y^2+8xy+C