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Popular >

y^'+y=e^{-t}-1

Solution

y^{^{'}} + y = e^{- t} - 1

Solution

y = \frac{t}{e ^{t}} - 1 + \frac{c _{1}}{e ^{t}}

Solution steps

y^{'} (t) + y = e^{- t} - 1

Solve linear ODE:

y = \frac{t}{e ^{t}} - 1 + \frac{c _{1}}{e ^{t}}

y = \frac{t}{e ^{t}} - 1 + \frac{c _{1}}{e ^{t}}

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Frequently Asked Questions (FAQ)

What is the solution for y^'+y=e^{-t}-1 ?
The solution for y^'+y=e^{-t}-1 is y= t/(e^t)-1+(c_{1})/(e^t)